Answer:
Conclusion:
As y = -3 MAKES the inequality TRUE.
Therefore, option D i.e. y = -3 is true.
Explanation:
Given the inequality
3y² + 2(y - 5) > 8
For y = 0
substitute y = 0 in the inequality
3y² + 2(y - 5) > 8
3(0)² + 2(0 - 5) > 8
3(0) + 2(-5) > 8
0 - 10 > 8
-10 > 8
FALSE!
-10 can not be greater than 8.
Hence, y = 0 does not make the inequality true.
For y = -1
substitute y = -1 in the inequality
3y² + 2(y - 5) > 8
3(-1)² + 2(-1 - 5) > 8
3(1) + 2(-6) > 8
3 - 12 > 8
-9 > 8
FALSE!
-9 can not be greater than 8.
Hence, y = 1 does not make the inequality true.
For y = -2
substitute y = -2 in the inequality
3y² + 2(y - 5) > 8
3(-2)² + 2(-2 - 5) > 8
3(4) + 2(-7) > 8
12 - 14 > 8
-2 > 8
FALSE!
-2 can not be greater than 8.
Hence, y = -2 does not make the inequality true.
For y = -3
substitute y = -3 in the inequality
3y² + 2(y - 5) > 8
3(-3)² + 2(-3 - 5) > 8
3(9) + 2(-8) > 8
27 - 16 > 8
11 > 8
TRUE!
11 is indeed greater than 8.
Hence, y = -3 MAKES the inequality TRUE.
Conclusion:
As y = -3 MAKES the inequality TRUE.
Therefore, option D i.e. y = -3 is true.