How do I solve 4(3-y)=6-2(1-3y) ?I'm getting y= -4 12-4y=6-2-6y 12-4y=4-6y 12+2y=4 2y= -8 y= -4

asked Dec 27, 2017 63.5k views

2 votes

How do I solve 4(3-y)=6-2(1-3y) ?I'm getting y= -4

12-4y=6-2-6y
12-4y=4-6y
12+2y=4
2y= -8
y= -4

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4 votes

The correct answer is y=-4 so you got it correct. You did every step right. :)

Alex Suo answered Dec 29, 2017

6.7k points

3 votes

I got y=2, however I'm terrible at math and have no idea if this is correct, im sorry

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