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In an engine, an almost ideal gas is compressed adiabatically to half its volume. In doing so, 2820 J of work is done on the gas.

Required:
a. How much heat flows into or out of the gas?
b. What is the change in internal energy of the gas?
c. Does its temperature rise or fall?

User YSC
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1 Answer

5 votes

Answer:


  1. Q=0

  2. U=2820
  3. Energy increases

Step-by-step explanation:

From the question we are told that

Work done
W=2820

a)Generally the heat flow for an adiabatic process is 0 (zero)


Q= U + W =>0


Q=0

b)Generally Change in internal energy of gas is mathematically given by

Since
W=-2820J

Therefore


U=2820

Giving


Q= 2820 -2820


Q=O

c)With increases in internal energy brings increase in temperature

Therefore

Energy increases

User Stenix
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