Question

Use the three steps to solve the problem.

Two planes leave an airport at noon. If the eastbound plane flies at 660 mph and the westbound plane flies at 600 mph, at what time will they be 2,000 miles apart? Round your answer to the nearest minute.

{
a0 p.m.}

Answer 1

y=660x+600x
where y is distance apart and x is time

2000=660x+600x
2000=x(660+600)
2000=x(1260)
2000/1260=x
1.587h= 1 hour and 25 minutes
at 1:25PM the plane will be 2000 miles apart

Answer 2

At 1:53 pm They will be 2,000 miles apart

Explanation:

Given :The eastbound plane flies at 660 mph and the westbound plane flies at 600 mph

To Find : At what time will they be 2,000 miles apart?

Solution :

The eastbound plane flies at 660 mph

Suppose after time t they will be 2,000 miles apart

So, distance traveled at this time by eastbound = Distance = Speed * time

Distance = 660t

The westbound plane flies at 600 mph

Suppose after time t they will be 2,000 miles apart

So, distance traveled at this time by west bound = Distance = Speed * time

Distance = 600t

So, to calculate t time at which they will be 2000 miles apart

`2000=(660+600)t`

`2000=1260t`

`(2000)/(1260) =t`

`1.58=t`

Since 1 hr = 60 minutes

So, 0.58 hours = 0.58*60 = 34.8 minutes

Thus after 1 hour 34 minutes they will be 2000 miles apart

Since they start at 12 noon

So, after 1 hour 53 minutes time will be 1:53 pm

Hence At 1:53 pm They will be 2,000 miles apart