Question

How can one fifthx − 2 = one thirdx + 8 be set up as a system of equations?

Answer 1

1/5x-2=1/3x+8
times both sides by 15
3x-30=5x+120
minus 3x both sides
-30=2x+120
minus 120 both sides
-150=2x
divide both sides by 2
-75=x

Answer 2

`y=(1)/(5)x-2`

`y=(1)/(3)x+8`

Explanation:

Given equation,

`(1)/(5)x-2=(1)/(3)x+8`

∵ When we solve an equation with help of graphing,

Then we make a system of equations by equating left side of the equation to a variable ( generally we put y ) and right side of the equation to the same variable,

Thus, by the statement,

The system of equation for solving the above equation would be,

`y=(1)/(5)x-2`

`y=(1)/(3)x+8`