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Calculate the mass of KI in grams required to prepare 9.00 ✕ 102 mL of a 1.40 M solution
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Mar 28, 2017
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Calculate the mass of KI in grams required to prepare 9.00 ✕ 102 mL of a 1.40 M solution
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Volume in liters:
9.00x10² mL / 1000 => 0.9 L
Molar mass KI => 166.0028 g/mol
Mass KI = volume x molar mass x molarity
Mass KI = 0.9 x 166.0028 x 1.40
=
209.16 g of KI
hope this helps!
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Apr 3, 2017
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