Question

X^2+4x-1/(x+2)^2=0 solve for x

Answer 1

x^2+4x-1/(x+2)^2=0
x^2 + 4x - 1 = 0


`(x^2+10x-7)/(x^2+10x+25) =0\\x^2+10x-7=0\\x= (-b\pm√(b^2-4ac))/(2a)`;
where a = 1, b = 4 and c = -1


`x=(-4\pm√(4^2-(4*1*(-1)))/(2*1)\\=(-4\pm√(16+4))/(2)=(-4\pm√(20))/(2)\\=(-4\pm√(4*5))/(2)=(-4\pm2√(5))/(2)=-2\pm√(5)\\=-2+√(5) \ or \ -2-√(5)\\x=0.24 \ or \ x = -4.24`