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Find the absolute extrema of the function on the closed interval. y = 3x2/3 − 2x, [−1, 1]

Find the absolute extrema of the function on the closed interval. y = 3x2/3 − 2x, [−1, 1]
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Find the absolute extrema of the function on the closed interval.
y = 3x2/3 − 2x, [−1, 1]

User Mente
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1 Answer

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I got x=1, hope this helps :)
User JATothrim
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