Question

A law firm has ten senior and eleven junior partners. A committee of 8 partners is selected at random to represent the firm at a conference. What is the probability that at least one of the junior partners is on the committee?

Answer 1

The probability that none of the junior partners is selected is given by:

`(10C8)/(21C8)=(1)/(4522)`
Therefore the probability that at least one junior partner is selected is:

`1-(1)/(4522)=(4521)/(4522)=0.99978`
The answer is 0.99978