Answer:
A) 0.8131 ≈ 0.81
B) 0.6322 ≈ 0.63
C) 0.7639 ≈ 0.77
Explanation:
A)
Total number of units
= 55 + 32 + 17 + 3
= 107
hence the probability that the failure involves a gas leak
= ( 55 + 32 ) / 107
= 0.8131
B) probability that there is evidence of electrical failure given tat there is a gas leak
P ( A / B ) =
P( A∩B ) = 55/107 = 0.5140
P ( B ) = ( 55 + 32 ) / 107 = 0.8131
hence P ( A / B ) = 0.5140 / 0.8131 = 0.6322
A = failure due to electrical
B = failure due to gas leak
C) Probability of a gas leak given that there is evidence of electrical failure
P ( B / A ) =
P ( B ∩ A ) = 0.5140
P( A ) = ( 55 + 17 ) / 107 = 0.6729
hence P ( B / A ) = 0.5140 / 0.6729 = 0.7639