70.3k views
10 votes
10

9
8
7
6
6 5
5
4
3
2
2
1
х
0 1 2 3 4 5 6 7 8 9 10

10 9 8 7 6 6 5 5 4 3 2 2 1 х 0 1 2 3 4 5 6 7 8 9 10-example-1

1 Answer

2 votes

Answer: 3/5

Explanation:


(6-3)/(5-0)=\boxed{(3)/(5)}

10 9 8 7 6 6 5 5 4 3 2 2 1 х 0 1 2 3 4 5 6 7 8 9 10-example-1
User Nauman
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