Question

A 5.5 gg sample of a substance contains only carbon and oxygen. Carbon makes up 35%% of the mass of the substance. The rest is made of oxygen. You are asked to determine the mass of oxygen in the sample. Which of the following expressions demonstrates a mathematical procedure to solve this problem using the proper order of operations?

a. ((100 - 35)/100) times 5.5 grams =
b. 100 - 35/100 times 5.5 grams =
c. 100 - (35/100) times 5.5 grams=

Answer 1

a. ((100 - 35)/100) times 5.5 grams = 3.575 g

Step-by-step explanation:

Given that:

The sample of carbon and oxygen = 5.5g

where carbon makes 35% of the mass of the substances.

It implies that oxygen will make: (100 - 35)% = 65%

Suppose y be the mass of the oxygen;

Then:

`y = ((100-35))/(100) * 5.5 \ g`

`y = \frac{(65)} {100} * 5.5 \ g`

`y = 3.575 \ g`

The mass of carbon
`= (35)/(100) * 5.5 \ g`

= 1.925 g