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Karen calculates the volume of cylinder A with a radius of 3 inches, and a height of 6 inches. The volume of this cylinder is 54π in3. Cylinder B also has a radius of 3 inches, but the height is doubled. What is the relationship between the volumes of the two cylinders?

User Indhi
by
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2 Answers

6 votes
the volume of B is twice that of A
if Vb=2hpir^2
and Va=hpir^2

compare
2hpir^2
hpir^2

twic as big

Volume of B is 2 times that of Volume of A
User Memet Olsen
by
7.2k points
3 votes

Answer:


2(\text{Volume of cylinder A})= \text{Volume of cylinder B }

Explanation:

Cylinder A:

Radius = 3 inches

Height = 6 inches

Volume =
54\pi inches^3

Cylinder B:

We are given that Cylinder B also has a radius of 3 inches, but the height is doubled.

Radius = 3 inches

Height =
2 * 6 =12 inches

Volume of cylinder B =
\pi r^(2)  h

=
\pi (3)^(2) * 12

=
108 \pi inches^3

Thus the volume of cylinder B is 108π cubic inches

Volume of Cylinder A = 54 π cubic inches

Since
2(54\pi )=108\pi

So, twice the volume of cylinder A = Volume of cylinder B


2(\text{Volume of cylinder A})= \text{Volume of cylinder B }

Hence the relationship between the volumes of the two cylinders is
2(\text{Volume of cylinder A})= \text{Volume of cylinder B }

User Ggfela
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