33.7k views
1 vote
Find the axis of symmetry for y = 4x2 + 16x - 2.

User Kedniko
by
8.6k points

2 Answers

1 vote

Final answer:

The axis of symmetry for the function y = 4x² + 16x - 2 is the vertical line x = -2, found by using the formula x = -b/(2a).

Step-by-step explanation:

The axis of symmetry for a quadratic equation in the form y = ax² + bx + c can be found using the formula x = -b/(2a). For the given equation y = 4x² + 16x - 2, a is 4 and b is 16.

Applying the formula, the axis of symmetry is x = -16/(2 × 4) = -16/8 = -2.

Therefore, the axis of symmetry for the equation y = 4x² + 16x - 2 is the vertical line x = -2.

User Blanen
by
7.5k points
6 votes
Simple....

graphing the parabola using the direction, vertex, focus, and axis of symmetry...

--->>>

Direction: Opens Up

Vertex: (-2,-18)

Focus:(-2,
- (287)/(16))

Axis of Symmetry: x=-2

Directrix: y=
- (289)/(16)

Thus, your answer.
User Pilou
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories