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Find the axis of symmetry for y = 4x2 + 16x - 2.

User Kedniko
by
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2 Answers

1 vote

Final answer:

The axis of symmetry for the function y = 4x² + 16x - 2 is the vertical line x = -2, found by using the formula x = -b/(2a).

Step-by-step explanation:

The axis of symmetry for a quadratic equation in the form y = ax² + bx + c can be found using the formula x = -b/(2a). For the given equation y = 4x² + 16x - 2, a is 4 and b is 16.

Applying the formula, the axis of symmetry is x = -16/(2 × 4) = -16/8 = -2.

Therefore, the axis of symmetry for the equation y = 4x² + 16x - 2 is the vertical line x = -2.

User Blanen
by
7.5k points
6 votes
Simple....

graphing the parabola using the direction, vertex, focus, and axis of symmetry...

--->>>

Direction: Opens Up

Vertex: (-2,-18)

Focus:(-2,
- (287)/(16))

Axis of Symmetry: x=-2

Directrix: y=
- (289)/(16)

Thus, your answer.
User Pilou
by
8.2k points