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4 votes
Solve the inequality

(x+1)/(x-8) \leq 0

1 Answer

3 votes

D:x\\ot=8\\ (x+1)/(x-8)\leq0\\ (x+1)(x-8)\leq0\\ x\in\langle-1,8\rangle\\\\ x\in\langle-1,8\rangle \wedge x\\ot=8\\ \boxed{x\in\langle-1,8)}
User Migue
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