Question

What is the mass percent of aluminum in Al(OH)3 the molar mass of AL = 26.98, H = 1.0079, and O = 16.00

Answer 1

Answer: 34.58%

Explanation:-

Mass percentage is the ratio of mass of a particular element present in the total mass of the substance in terms of percentage.

`Mass\ %=\frac{\text{Mass of} Al}{\text{Mass of} Al(OH)_3}* 100\ %`

Given: mass of AL = 26.98, H = 1.0079, and O = 16.00

Thus mass of
`Al(OH)_3=26.98+3* 16+3* 1.0079=78.0037g`

Putting the values in the equation:

`Mass\%=(26.98g)/(78.0037g/mol)* 100\ %=34.58\ %`

Thus mass percent of aluminum in
`Al(OH)_3` is 34.58%.

Answer 2

mass percentage = (mass of Al)/(Total mass) * 100
= (26.98) / (26.98 + 3 * (1.0079 + 16)) * 100
= 34.59%