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Use log_2 7 is about 2.8074 and log_2 5 is about 2.3219 to approximate log_2 175?
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Use log_2 7 is about 2.8074 and log_2 5 is about 2.3219 to approximate log_2 175?

User Dylan Lacey
by
9.4k points

2 Answers

6 votes

Answer:

it would be log 1/2 5

Explanation:

User Fabricio Colombo
by
8.4k points
6 votes
remembe

log_ax+log_ay=log_a(xy)


so
notice
7*5*5=175

so we want to multiply them
add


log_27+log_25+log_25=log_2175=
(2.8074)(2.3219)(2.3219)=15.135309933114
User Mikael Rousson
by
8.4k points
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