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A 208-long road is divided into 16 parts of equal length.Mr.Ward paints a 4-meter-long strip in each part.How many total meters are not painted in the 208 meters of road?

User Kanji
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2 Answers

5 votes
208 % 16 = 13
13 - 4 = meters not painted in a part = 9
9 × 16 (parts) = 144 meters of road not painted
User Tom Crockett
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6 votes

Answer

Find out the how many total meters are not painted in the 208 meters of road .

To prove

Let us assume that the total meters are not painted in the 208 meters of road be x.

As given

A 208-long road is divided into 16 parts of equal length.


Each\ road\ length\ when\ divided\ into\ 16\ equal\ parts = (208)/(16)

Each road length when divided into 16 equal parts = 13 meters

As given

Mr.Ward paints a 4-meter-long strip in each part.

Mr.Ward not paints in each part = 13 - 4

= 9 meters

Thus

Total meters are not painted in the 208 meters of road = 9 × 16

= 144 meters

Therefore 144 meters are not painted in the 208 meters of road .




User Mpdc
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