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Convert to standard circle form x^(2) +y ^(2) -6x-4y-12=0
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Convert to standard circle form
x^(2) +y ^(2) -6x-4y-12=0

User Inkeliz
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1 Answer

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x^2 + y^2 - 6x - 4y - 12 = 0
x^2 - 6x + y^2 - 4y = 12
x^2 - 6x + 9 + y^2 - 4y + 4 = 12 + 9 + 4
(x - 3)^2 + (y - 2)^2 = 25
User Greg Berger
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