Question

`f(x)=-3x^(2) +6x+7` the equation of the axis of symmetry

Answer 1

`x=1`

Explanation:

Complete the square

`f(x)=-3x^2+6x+7`

`y=-3x^2+6x+7`

`y-10=-3x^2+6+7-10`

`y-10=-3x^2+6x-3`

`y-10=-3(x^2-2x+1)`

`y-10=-3(x-1)^2`

`y=-3(x-1)^2+10`

Identify vertex and axis of symmetry

`y=a(x-h)^2+k`

`(h,k)\rightarrow(1,10)`

`x=h\rightarrow x=1`