Question

LeAnn is purchasing giftwrap for a box that measures 8 inches long, 6 inches wide, and 6 inches tall. Calculate the total area of the box that will be covered in gift wrap. Show all of your work for full credit.

Answer 1

A box shape in three dimensional space. Formally, a polyhedron for which all faces are rectangles.
Rectangular Parallelepiped
Volume = lwh 8*6*6=288Lateral Surface Area = 2lh + 2wh=94Surface Area = 2lw + 2lh + 2wh=288

Answer 2

Let

L---------> the length side of the box

W--------> the width side of the box

H-------> the height of the box

we know that

`L=8\ in\\W=6\ in\\H=6\ in`

the surface area of the box is equal to

`S=2*area\ of\ the\ base+perimeter\ of\ the\ base*H`

Find the area of the base

`A=L*W=8*6=48\ in^(2)`

Find the perimeter of the base

`P=2*L+2*W=2*8+2*6=28\ in`

Find the surface area

`S=2*48+28*6`

`S=264\ in^(2)`

therefore

the answer is

the total area of the box that will be covered in gift wrap is
`264\ in^(2)`