Question

What is the distance between P(−4, 3) and Q(6, 1)? Round to the nearest tenth.

Answer 1

like pythagorean theorem

Distance between ponints (x1,y1) and (x2,y2) is

D=
`√((x2-x1)^2+(y2-y1)^2)`
points are (-4,3) and (6,1)

D=
`√((6-(-4))^2+(1-3)^2)`
D=
`√((6+4)^2+(-2)^2)`
D=
`√((10)^2+4)`
D=
`√(100+4)`
D=
`√(104)`
D=2√26

the distance is 2√26