1 Answer

James Khoury · Answer 1 · 2017-07-08T16:07:07+0000

sin³(x)cos⁴(x) = sin(x)[cos⁴(x) - cos⁶(x)]
sin(x) sin(x)
sin²(x)cos⁴(x) = cos⁴(x) - cos⁶(x)
sin²(x)cos⁴(x) = cos⁴(x)[1] - cos⁴(x)[cos²(x)]
sin²(x)cos⁴(x) = cos⁴(x)[1 - cos²(x)}
cos⁴(x) cos⁴(x)
sin²(x) = 1 - cos²(x)
+ cos²(x) + cos²(x)
1 = 1

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Related questions

Other Questions