Question

Letx(t) = t ^ 3 - 4t ^ 2 + t and y(t) = t ^ 2 - 3t + 3

Answer 1

Step-by-step explanation:

The functions are given below as

`\begin{gathered} x(t)=t^3-4t^2+t \\ y(t)=t^2-3t+3 \end{gathered}`

Part 1:

To figure out x(2) , we will put t=2

`\begin{gathered} x(t)=t^(3)-4t^(2)+t \\ x(2)=2^3-4(2^2)+2 \\ x(2)=8-16+2 \\ x(2)=-6 \end{gathered}`

Hence,

The final answer is

`x(2)=-6`

Part 2:

To figure out y(2), we will put t=2

`\begin{gathered} y(t)=t^(2)-3t+3 \\ y(2)=2^2-3(2)+3 \\ y(2)=4-6+3 \\ y(2)=1 \end{gathered}`

Hence,

The final answer is

`y(2)=1`