Question

If a gum-ball machine contains 22 red gum balls, 46 yellow gum balls, 14 green gum balls, and 18 orange gum balls, what is the probability that a gum ball chosen at random will be green?

A: 23/50
B: 11/50
C: 7/50
D: 9/50

Answer 1

The total number of balls is 22+46+14+18 = 100

The number of green balls is 14

We then divide the number of green balls by the total number of balls:

14/100

This can be simplified to 7/50 by taking out a factor of 2

Therefore the answer is c