Question

Find three consecutive even integers such that their sum is 50 more than the largest integer

Answer 1

This is how I'd solve it:

1st no. = 2x (2x)+(2x+2)+(2x+4)=(2x+4)+50
2nd no. = 2x+2 6x+6=2x+54
3rd no. = 2x+4 4x=48
x=12

Substitute the x value, and your numbers are 24, 26, and 28. To check: their sum (78) is 50 more than the largest integer (28).