Find three consecutive even integers such that their sum is 50 more than the largest integer

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asked Sep 14, 2017 59.2k views

1 Answer

Danielstn · Answer 1 · 2017-09-21T07:46:07+0000

This is how I'd solve it:

1st no. = 2x (2x)+(2x+2)+(2x+4)=(2x+4)+50
2nd no. = 2x+2 6x+6=2x+54
3rd no. = 2x+4 4x=48
x=12

Substitute the x value, and your numbers are 24, 26, and 28. To check: their sum (78) is 50 more than the largest integer (28).

Find three consecutive even integers such that their sum is 50 more than the largest integer

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