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How many moles of Fe2O3 are in 209 g of the compound?

How many moles of Fe2O3 are in 209 g of the compound?
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How many moles of Fe2O3 are in 209 g of the compound?

User Cong Wang
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m = 209g
M = 56 * 2 + 16 * 3 = 160 g/mol

n = m/M = 209g / 160 g/mol = 1,30625mol
User Bpfrd
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