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If the unicorn seat on a merry–go–round is 5 feet from the center, and the merry–go–round completes a full rotation in 6 seconds, how many feet does the unicorn travel in one second?

User Hradecek
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2 Answers

1 vote

The correct answer is

5.23

:)

User Kosmotaur
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8.5k points
2 votes
The answer is 5.23 ft/second

The way I got this answer was first finding the circumference of the merry-go-round using the equation
C=2 \pi r, where r represents the radius, which is the distance from the center of a circle.

So your equation should look like this
C=2 \pi(5). I used the rounded term of 3.14 for
\pi

Once you multiply those terms, you should get the answer, 31.4. Now this is the total distance around the merry-go-round in feet. So, if it takes 6 seconds to make a full rotation and we are trying to find the amount offeet traveled in one second, we should divide the circumference (31.4) by 6 to give us our answer.

So, 31.4÷6=5.2333...ft/second

And I rounded the answer to the nearest hundredth to get 5.23 feet/second
User Dustydojo
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