Question

What is the mass of 3.8 × 10^24 atoms of argon (ar)? 0.0039 g 0.16 g 6.3 g 250 g

Answer 1

Atomic mass Ar => 39.948 a.m.u

39.948 g --------------- 6.02x10²³ atoms
?? g -------------------- 3.8x10²⁴ atoms

(3.8x10²⁴) x 39.948 / 6.02x10²³ => 250 g

hope this helps!

Answer 2

Answer : The mass of argon will be, 250 grams

Explanation : Given,

Number of atoms of argon =
`3.8* 10^(24)`

As we know that, 1 mole of substance contains
`6.022* 10^(23)` number of atoms.

First we have to calculate the moles of argon.

As,
`6.022* 10^(23)` number of argon atoms present in 1 mole of argon

So,
`3.8* 10^(24)` number of argon atoms present in
`(3.8* 10^(24))/(6.022* 10^(23))=6.31` mole of argon

The moles of argon = 6.31 mole

Now we have to calculate the mass of argon.

`\text{Mass of }Ar=\text{Moles of }Ar* \text{Molar mass of }Ar`

`\text{Mass of }Ar=(6.31mole)* (40g/mole)=252.4g`

The mass of argon = 252.4 grams that is approximately equal to 250 grams.

Therefore, the mass of argon will be, 250 grams.