Question

SOMEONE I NEED HELP PLEASE! ITS BEEN 10 HOURS NO ANSWER PLEASE HELP ME! CAN YOU SOLVE THIS PLEASE?

Julia measured the high temperature in her town for one week. Using the chart below, find the mean absolute deviation for the high temperatures. Be sure to show your work for finding: the mean of the set data, the distance of each number from the mean, and the absolute deviation

This is the chart :Sunday 50, Monday 56, Tuesday 52, Wednesday 46, Thursday 48 , Friday 42, and Saturday 38

Answer 1

mean

7 days
add them up and divide by 7
50+56+52+46+48+42+38=332
divide that by 7
47.428 about

distance each is from the mean
50 is 2.572 from it
56 is 8.572 from it
52 is 4.572 from it
46 is 1.428 from it
48 is 0.562 from it
42 is 5.428 from it
38 is 9.428 from it

add those and average them
(2.572+8.572+4.572+1.428+0.562+5.428+9.428)/7=4.652

absolute deviation is 4.652 aprox