Question

How many moles of Fe2o3 are in 161 g of the compound ?

Answer 1

To calculate the moles of Fe2O3 in 161 g, divide the mass by the molar mass of Fe2O3, which results in approximately 1.01 moles.

Step-by-step explanation:

To calculate how many moles of Fe2O3 are in 161 g of the compound, you use the molar mass of iron(III) oxide, which is 159.70 g/mol. Using the formula:

Number of moles = mass (g) / molar mass (g/mol)

You can find the moles of Fe2O3:

Number of moles = 161 g / 159.70 g/mol = 1.008 moles

Your final answer, rounded to three significant figures, is 1.01 moles of Fe2O3.

Answer 2

m = 161g
M = 56 * 2 + 16 * 3 = 160g/mol

n = m/M = 161g / 160g/mol = 1,00625 mol