Answer;
Explanations:
In order to get the required volume in liters of hydrogen, we will use the general gas equation expressed as:
P1 and P2 are the initial and final pressure of the gas
V1 and V2 are the initial and final volume of the gas
T1 and T2 are the initial and final temperatures of the gas:
Given the following parameters:
![\begin{gathered} P_1=755\operatorname{mm}Hg \\ V_1=1.23L \\ T_1=0^0C=273K \\ P_2=0.97\text{atm}=737.2\operatorname{mm}Hg \\ T_2=50+273=323K_{} \\ V_2=\text{?} \end{gathered}]()
Substitute the given parameters into the formula as shown:
![\begin{gathered} V_2=(P_1V_1T_2)/(P_2T_1) \\ V_2=\frac{755\cancel{\operatorname{mm}Hg}*1.23L*323\cancel{K}}{737.3\cancel{\operatorname{mm}Hg}*273\cancel{K}} \\ V_2=(755*1.23L*323)/(737.3*273) \\ V_2=(299,953.95)/(201282.9) \\ V_2=1.49L \end{gathered}]()
Hence the volume, in liters that the same gas will occupy at 0.97 atm and a temperature of 50 degrees Celsius is 1.49L