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What is the perimeter of ΔBDE?

What is the perimeter of ΔBDE?-example-1

2 Answers

7 votes
a = √1² + 2²
a = √1 + 4
a = √5
a ≈ 2.23

b = 4

c = √3² + 2²
c = √9 + 4
c = √13
c ≈ 3.6

P = a + b + c
P = 2.23 + 4 + 3.6
P = 6.23 + 3.6
P = 9.83

Perimeter of ΔBDE = 9.83 units
User DJeanCar
by
7.3k points
5 votes

Answer:

9.84 units.

Explanation:

We will use distance formula to find the perimeter of the given triangle.


\text{Distance}=√((x_2-x_1)^2+(y_2-y_1)^2)


\text{Distance between B and D}=√((2-1)^2+(4-2)^2)


\text{Distance between B and D}=√((1)^2+(2)^2)


\text{Distance between B and D}=√(1+4)


\text{Distance between B and D}=√(5)


\text{Distance between D and E}=√((5-2)^2+(2-4)^2)


\text{Distance between D and E}=√((3)^2+(-2)^2)


\text{Distance between D and E}=√(9+4)


\text{Distance between D and E}=√(13)

We can see the distance between B and E is 4 units (5-1).


\text{Perimeter of triangle BDE}=√(5)+√(13)+4


\text{Perimeter of triangle BDE}=9.841619252\approx 9.84

Therefore, the perimeter of triangle BDE is 9.84 units.

User Richard Huxton
by
8.8k points

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