Question

If a seed is planted, it has a 95% chance of growing into a healthy plant.If 6 seeds are planted, what is the probability that exactly 2 don't grow?

Answer 1

The problem is under binomial distribution probability.

The formula to be used is shown below

Fot the question before us,

n = 6

x = 2

p = 1 - 95% = 1 - 0.95 = 0.05

q = 95% = 0.95

Sunstituting the values into the above formula, we have

`\begin{gathered} p_2=^6C_2(0.05)^2(0.95)^(6-2) \\ p_2=^6C_2(0.05)^2(0.95)^(6-2) \\ p_2=15(0.0025)(0.81450625) \\ p_2=0.0305 \\ p_2=(3.05)/(100) \\ p_2=3.05\text{\%} \end{gathered}`

The answer is 3.05%