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How many solutions does the equation have?

4(z−5)+2=4z−184(z−5)+2=4z−18

A. 0

B. 1

C. many

2 Answers

2 votes
I hope this helps you
How many solutions does the equation have? 4(z−5)+2=4z−184(z−5)+2=4z−18 A. 0 B. 1 C-example-1
User Sebastian Giro
by
6.4k points
4 votes

Answer:

option C (many)

Explanation:


4(z-5)+2=4z-18

Distribute the numbers inside the parenthesis


4(z-5)+2=4z-18


4z-20+2=4z-18

Combine like terms

Subtract 4x from both sides


4z-20+2=4z-18


-20+2=-18


-18=-18

Both sides are equal. So there are more than one solution for x

Answer is option C (many)

User Kralizek
by
6.8k points
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