Question

Solve for h.

6h−(9−3h)=6−3(h+2)

Answer 1

We should take this problem step by step, following the rules of PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)

1) Since we can't simplify anything in the parentheses, and there are no exponents, we start with multiplication. The integer outside of the first set of parentheses is -1 NOT 1, and the integer outside of the second set is -3 NOT 3. We multiply what is in the parentheses by these numbers. Therefore...

6h-9+3h=6-3h-6

Next to simplify things, we should combine like terms.

9h-9= -3h

Lastly we isolate the variable by subtracting 9h from both sides.

-9= -12h

Then we divide both sides by -12,

-9/-12= h

3/4=h

Hope this helped!!!

Answer 2

`h=(3)/(4)`

Explanation:

"Solve for h" means that we have to clear h.

We have the expression:
`6h-(9-3h)=6-3(h+2)`

First we have to apply distributive property:

Observation: Distributive property is: a(b+c)=ab+ac

We are going to rewrite the expression as:

`6h+(-1)(9-3h)=6-3(h+2)\\6h-9+3h=6-3h-6\\6h-9+3h=-3h`

Now we have to add 3h to both sides of the equation.

`6h-9+3h=-3h\\6h-9+3h+3h=-3h+3h\\6h+3h+3h-9=0\\12h-9=0`

Add 9 to both sides of the equation:

`12h-9=0\\12h-9+9=9\\12h=9`

Finally divide both sides in 12:

`12h=9\\(12h)/(12)=(9)/(12)\\\\h=(3)/(4)`

Then the result is:

`h=(3)/(4)`