Question

You flip a coin twice what is the probability of getting heads and then getting heads

Answer 1

The probability that a single event A occurs is:

`P=\frac{\text{ number of favorable outcomes of A}}{\text{ total number of outcomes}}`

The probability of two consecutive events A and B is:

`P=P(A)*P(B)`

Let's calculate the probability of event A: getting heads.

Favorable outcome: heads.

Number of favorable outcomes: 1.

Total outcomes: heads, tails.

Number of total outcomes: 2.

So:

`P(A)=(1)/(2)`

Let's calculate the probability of event B: getting heads in the second flip.

Favorable outcome: heads.

Number of favorable outcomes: 1.

Total outcomes: heads, tails.

Number of total outcomes: 2.

So:

`P(B)=(1)/(2)`

Finally, let's find the probability of getting heads twice.

`\begin{gathered} P=P(A)*P(B) \\ P=(1)/(2)*(1)/(2)=(1)/(4) \end{gathered}`

Finding the probability in percentual:

`\begin{gathered} P=(1)/(4)*100 \\ P=25\% \end{gathered}`

Answer: 1/4 = 25%.