Final answer:
The largest interval that includes x = 0 for which the given initial-value problem has a unique solution is (4, ∞).
Step-by-step explanation:
To find the largest interval which includes x = 0 for which the given initial-value problem has a unique solution, we can use the existence and uniqueness theorem for second-order linear homogeneous differential equations. The given equation is (x − 4)y'' + 5y = x, with initial conditions y(0) = 0 and y'(0) = 1.
To apply the theorem, we first divide the equation by (x - 4) to get y'' + (5/(x - 4))y = x/(x - 4). Now, let's analyze the interval of (x - 4). When x - 4 > 0, the interval is (4, ∞). When x - 4 < 0, the interval is (-∞, 4).
Since we are interested in finding the interval that includes x = 0, we need the interval where x - 4 > 0, which is (4, ∞). Therefore, the largest interval that includes x = 0 for which the given initial-value problem has a unique solution is (4, ∞).