Question

Look at the circuit below. What is the voltage between points B and C?OA. 3 VOB. 0.75 V15001.5 VD

Answer 1

Answer: .75

Step-by-step explanation:

Answer 2

Given:

The potential across the battery is

`V=1.5\text{ V}`

The resistance of each bulb in series is

`R=150\text{ }\Omega`

To find:

The voltage between points B and C

Explanation:

The equivalent resistance of the bulbs is,

`\begin{gathered} R_(eq)=R+R \\ =150+150 \\ =300\text{ }\Omega \end{gathered}`

The current in the circuit is,

`\begin{gathered} I=(V)/(R_(eq)) \\ =(1.5)/(300) \\ =5*10^(-3)\text{ A} \end{gathered}`

The voltage drop across B and C is the same as the voltage drop across the first bulb, which is,

`\begin{gathered} V_(BC)=I* R \\ =5*10^(-3)*150 \\ =0.75\text{ V} \end{gathered}`

Hence, the required voltage drop is 0.75 V.