Register

​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 68 cm when the weight is 2 ​kg…

​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 68 cm when the weight is 2 ​kg…
79.7k views
0 votes
​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is

68 cm when the weight is 2 ​kg, what is the distance when the weight is 5 ​kg?

User Sfk
by
8.3k points

1 Answer

1 vote
It would just be 2x68, in the sense that the original equation for Hooke's Law is F=kX. In your equation, w is k and X is D. the answer is 136cm for 2kg and 340cm  for 5kg. Tell me if this is wrong please.
User BloodAxe
by
8.1k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!