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​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is 68 cm when the weight is 2 ​kg, what is the distance when the
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​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is

68 cm when the weight is 2 ​kg, what is the distance when the weight is 5 ​kg?

User Sfk
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It would just be 2x68, in the sense that the original equation for Hooke's Law is F=kX. In your equation, w is k and X is D. the answer is 136cm for 2kg and 340cm  for 5kg. Tell me if this is wrong please.
User BloodAxe
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