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A piece of aluminum with a mass of 3.05 g initially at a temperature of 10.8 °C is heated to a temperature of 20.

Assume that the specific heat of aluminum is 0.901 J/(g°C).
How much heat was needed for this temperature change to take place?

User Prasvin
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1 Answer

4 votes

Answer:

25.3J

Step-by-step explanation:

Given parameters:

Mass of aluminum = 3.05g

Initial temperature = 10.8 °C

Final temperature = 20 °C

Specific heat = 0.9J/g °C

Unknown:

Amount of heat needed for the temperature to change = ?

Solution:

To solve this problem, we use the expression:

H = m C Ф

H is the amount of heat

m is the mass

C is the specific heat capacity

Ф is the change in temperature

H = 3.05 x 0.901 x (20 - 10.8) = 25.3J

User Aberdat
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