Question

What is the mass of 5.22×10^21 platinum atoms??

Answer 1

Atomic mass platinum = 195.084 a.m.u

195.084 g -------------- 6.02x10²³ atoms
?? g -------------------- 5.22x10²¹ atoms

( 5.22x10²¹) x 195.084 / 6.02x10²³ => 1.691 g

hope this helps!

Answer 2

1.69g

Step-by-step explanation:

To solve the problem you need to know the Avogadro´s number and the molar mass of the Platinum.

The Avogadro´s number is
`6.022*10^(23)(atoms)/(mol)`. For the platinum it means that there are
`6.022*10^(23)(atoms)/(mol)` atoms of platinum for each mol.

And the molar mass for the platinum is
`195.084(g)/(mol)`, that is the mass in grams of each mol of platinum.

So, with this information we can solve the problem as follows:

`5.22*10^(21)atomsofPt*(1molofPt)/(6.022*10^(23)atomsofPt)*(195.084g)/(1molofPt)=1.69g` of Pt