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5 votes
\_(o-o)_/
What do I do????

\_(o-o)_/ What do I do????-example-1
User Manoj I
by
7.6k points

2 Answers

3 votes
find u 2 pairs of points on ur line. (10,3)(0,-2)

now we use the slope formula to find the slope.
slope(m) = (y2 = y1) / (x2 - x1)
set 1 : (10,3)...x1 = 10 and y1 = 3
set 2 : (0,-2)...x2 = 0 and y2 = -2
now we sub
slope(m) = (-2 - 3) / (0 - 10) = -5/-10 = 1/2

now we use y = mx + b
slope(m) = 1/2
u can use either of ur sets of points
(0,-2)...x = 0 and y = -2
now we sub and solve for b, the y int
-2 = 1/2(0) + b
-2 = b

so ur equation of ur line is : y = 1/2x + (-2) or y = 1/2x - 2
User Frank Shearar
by
8.6k points
3 votes
y=mx+b
m=slope
b=yintercept

find slope and y intercept

slope is rise/run
it goes up y units and goes x units to the right

so
we see it goes up 2 and to the right 4
2/4=1/2
slope=1/2

yintercept is where the line crosses the y axis (up and down line)
it crosses at y=-2

y=mx+b
m=1/2
b=-2
y=1/2x-2


answer is 2nd option
User Rodrigo Belli
by
7.9k points

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