Question

What's $1800 at 9% compounded annually for 6 years?

Answer 1

1800x 1.09^6 = 3018.78 (rounded)

hope this helps :)

Answer 2

`A=P(1+ (r)/(n))^(nt)`
A=future amount
P=present amount
r=rate in decimal
n=number of times per year compounded
t=time in years

A=?
P=1800
r=0.09
n=1
t=6

`?=1800(1+ (0.09)/(1))^((1)(6))`

`?=1800(1+0.09)^6`

`?=1800(1.09)^6`
?=3018.78

answer is $3,018.78