Question

1/x - 1/(x+1) ≤ 0 Please help quickly

Answer 1

`(1)/(x)- (1)/(x+1)= ((x+1)-x)/(x(x+1))= (1)/(x(x+1)) \leq 0`

Therefore x(x+1)≤0, and if two numbers multiply to a negative number, one of them has to be negative and the other has to be positive. In this case, because x+1>x, x≤0, and x+1≥0

Therefore -1≤x≤0, and x can take up the value of any real number in the interval [-1,0]