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44 votes
your middle school is having two carnivals admission into the first Carnival is $7 in each game inside the carnival cost $3 in the second Carnival admission is $10 and each game cost $2. Which inequality can be used to find G the minimum number of games that can be played by the total charge at 2nd Carnival will be less than total charge at the first Carnival

User Fahri
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1 Answer

26 votes
26 votes

The cost of the first carnival can be given by the following expression:


c_1(x)=7+3\cdot x

Where c1 is the total cost and x is the number of games played. The cost for the second one is:


c_2(x)=10+2\cdot x

Where c2 is the total cost and x is the number of games played. To find the minimum number of games that we need to play on the second carnival for it to be lower than the first, we need to solve the following inequality:

[tex]\begin{gathered} c_2For the cost on the second carnival to be lower than the first we need to play at most 3 games.
User KCP
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