Question

(-3,-3) ; parallel to -x+3y=9

Answer 1

Rewriting the equation in the form y=mx+c
-x+3y=9
3y=x+9
y=
`(1)/(3) x+3`
Gradient is 1/3
Since parallel lines have similar gradients,

`(y--3)/(x--3)= (1)/(3)`
y+3=
`(1)/(3) (x+3)`
y+3=
`(1x)/(3) +1`
y=
`(1x)/(3) -2`