Please see below solution:
The electric field just outside its surface is = 2 , where is a radius of sphere, is a charge of sphere, = 1 4ε0 . The electric field is = 1 4ε0 2 = 1 ε0 ∙ = σ ε0 , where = 4 2 is an area of sphere, σ = Q S is a surface charge density. Answer: .