Question

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account? Which of the following equations could be used to solve the problem? 0.02x + 0.04(800) = 112 0.02x + 0.04(x + 800) = 112 0.04x + 0.02(x + 800) = 112

Answer 1

112 dallors interest beca0.02x + 0.04(800) = 112 0.02x + 0.04(x + 800) = 112 0.04x + 0.02(x + 800) = 112 use 

Answer 2

0.02x + 0.04(800) = 112

Explanation:

Let the unknown amount be x

The amount is invested at 2 % interest so the intrest will be $ 0.02x

However, another amount, this time $ 800 is invested at 4 % interest. This gives:

0.04 (800)

The total amount at the end of the year will be = $ 112

Therefore, the sum of the two interests will be
`\\$ 0.02x+ 0.04($800) = $ 112.00`