Question

If a gallon of paint covers 400 square feet, how many gallons are needed to paint a retaining wall that is 269 feet long and 4 feet high ? Round the answer up to the nearest whole gallon

Answer 1

To paint a retaining wall that is 269 feet long and 4 feet high, covering 1076 square feet in total, and given that one gallon of paint covers 400 square feet, you would need to round up 2.69 gallons to 3 gallons of paint.

Step-by-step explanation:

To calculate the amount of paint needed to cover a retaining wall, we first need to determine the total area of the wall. We do this by multiplying the wall's length by its height:

269 feet (length) × 4 feet (height) = 1076 square feet (total area)

Next, we determine how many gallons are needed by dividing the total area by the coverage rate per gallon:

1076 square feet ÷ 400 square feet per gallon = 2.69 gallons

Since we can't buy a fraction of a gallon, we'll need to round up to the nearest whole gallon. Therefore, we will need 3 gallons to paint the entire wall.

Answer 2

The area of a rectangular shape is given by

`A=l* b`

Given:

It is given that a gallon of paint covers 400 square feet, and wall is 269 feet long and 4 feet high .

Now the area of wall will be

`A=269*4`

Since,

`\begin{gathered} 400\text{ sq f}eet=\text{ 1gallon} \\ 1\text{ sq f}eet=(1)/(400)gallon \\ 269*4\text{ sq f}eet=(1)/(400)*269*4 \\ =(269)/(100) \\ =2.69\text{ gallon} \\ =3\text{ galllon} \end{gathered}`

So, the ewall requires approx 3 gallon of paint.